Integrand size = 19, antiderivative size = 152 \[ \int \frac {\sqrt {x}}{\left (a x+b x^3\right )^{9/2}} \, dx=\frac {\sqrt {x}}{7 a \left (a x+b x^3\right )^{7/2}}+\frac {2}{7 a^2 \sqrt {x} \left (a x+b x^3\right )^{5/2}}+\frac {16}{21 a^3 x^{3/2} \left (a x+b x^3\right )^{3/2}}+\frac {32}{7 a^4 x^{5/2} \sqrt {a x+b x^3}}-\frac {128 \sqrt {a x+b x^3}}{21 a^5 x^{7/2}}+\frac {256 b \sqrt {a x+b x^3}}{21 a^6 x^{3/2}} \]
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Time = 0.15 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {2040, 2041, 2039} \[ \int \frac {\sqrt {x}}{\left (a x+b x^3\right )^{9/2}} \, dx=\frac {256 b \sqrt {a x+b x^3}}{21 a^6 x^{3/2}}-\frac {128 \sqrt {a x+b x^3}}{21 a^5 x^{7/2}}+\frac {32}{7 a^4 x^{5/2} \sqrt {a x+b x^3}}+\frac {16}{21 a^3 x^{3/2} \left (a x+b x^3\right )^{3/2}}+\frac {2}{7 a^2 \sqrt {x} \left (a x+b x^3\right )^{5/2}}+\frac {\sqrt {x}}{7 a \left (a x+b x^3\right )^{7/2}} \]
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Rule 2039
Rule 2040
Rule 2041
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {x}}{7 a \left (a x+b x^3\right )^{7/2}}+\frac {10 \int \frac {1}{\sqrt {x} \left (a x+b x^3\right )^{7/2}} \, dx}{7 a} \\ & = \frac {\sqrt {x}}{7 a \left (a x+b x^3\right )^{7/2}}+\frac {2}{7 a^2 \sqrt {x} \left (a x+b x^3\right )^{5/2}}+\frac {16 \int \frac {1}{x^{3/2} \left (a x+b x^3\right )^{5/2}} \, dx}{7 a^2} \\ & = \frac {\sqrt {x}}{7 a \left (a x+b x^3\right )^{7/2}}+\frac {2}{7 a^2 \sqrt {x} \left (a x+b x^3\right )^{5/2}}+\frac {16}{21 a^3 x^{3/2} \left (a x+b x^3\right )^{3/2}}+\frac {32 \int \frac {1}{x^{5/2} \left (a x+b x^3\right )^{3/2}} \, dx}{7 a^3} \\ & = \frac {\sqrt {x}}{7 a \left (a x+b x^3\right )^{7/2}}+\frac {2}{7 a^2 \sqrt {x} \left (a x+b x^3\right )^{5/2}}+\frac {16}{21 a^3 x^{3/2} \left (a x+b x^3\right )^{3/2}}+\frac {32}{7 a^4 x^{5/2} \sqrt {a x+b x^3}}+\frac {128 \int \frac {1}{x^{7/2} \sqrt {a x+b x^3}} \, dx}{7 a^4} \\ & = \frac {\sqrt {x}}{7 a \left (a x+b x^3\right )^{7/2}}+\frac {2}{7 a^2 \sqrt {x} \left (a x+b x^3\right )^{5/2}}+\frac {16}{21 a^3 x^{3/2} \left (a x+b x^3\right )^{3/2}}+\frac {32}{7 a^4 x^{5/2} \sqrt {a x+b x^3}}-\frac {128 \sqrt {a x+b x^3}}{21 a^5 x^{7/2}}-\frac {(256 b) \int \frac {1}{x^{3/2} \sqrt {a x+b x^3}} \, dx}{21 a^5} \\ & = \frac {\sqrt {x}}{7 a \left (a x+b x^3\right )^{7/2}}+\frac {2}{7 a^2 \sqrt {x} \left (a x+b x^3\right )^{5/2}}+\frac {16}{21 a^3 x^{3/2} \left (a x+b x^3\right )^{3/2}}+\frac {32}{7 a^4 x^{5/2} \sqrt {a x+b x^3}}-\frac {128 \sqrt {a x+b x^3}}{21 a^5 x^{7/2}}+\frac {256 b \sqrt {a x+b x^3}}{21 a^6 x^{3/2}} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.52 \[ \int \frac {\sqrt {x}}{\left (a x+b x^3\right )^{9/2}} \, dx=\frac {\sqrt {x} \left (-7 a^5+70 a^4 b x^2+560 a^3 b^2 x^4+1120 a^2 b^3 x^6+896 a b^4 x^8+256 b^5 x^{10}\right )}{21 a^6 \left (x \left (a+b x^2\right )\right )^{7/2}} \]
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Time = 2.09 (sec) , antiderivative size = 81, normalized size of antiderivative = 0.53
method | result | size |
gosper | \(-\frac {x^{\frac {3}{2}} \left (b \,x^{2}+a \right ) \left (-256 b^{5} x^{10}-896 a \,b^{4} x^{8}-1120 a^{2} b^{3} x^{6}-560 a^{3} b^{2} x^{4}-70 a^{4} b \,x^{2}+7 a^{5}\right )}{21 a^{6} \left (b \,x^{3}+a x \right )^{\frac {9}{2}}}\) | \(81\) |
default | \(-\frac {\sqrt {x \left (b \,x^{2}+a \right )}\, \left (-256 b^{5} x^{10}-896 a \,b^{4} x^{8}-1120 a^{2} b^{3} x^{6}-560 a^{3} b^{2} x^{4}-70 a^{4} b \,x^{2}+7 a^{5}\right )}{21 x^{\frac {7}{2}} \left (b \,x^{2}+a \right )^{4} a^{6}}\) | \(83\) |
risch | \(-\frac {\left (b \,x^{2}+a \right ) \left (-14 b \,x^{2}+a \right )}{3 a^{6} x^{\frac {5}{2}} \sqrt {x \left (b \,x^{2}+a \right )}}+\frac {\left (b \,x^{2}+a \right ) x^{\frac {3}{2}} \left (158 b^{3} x^{6}+511 a \,b^{2} x^{4}+560 a^{2} b \,x^{2}+210 a^{3}\right ) b^{2}}{21 a^{6} \left (x^{8} b^{4}+4 a \,b^{3} x^{6}+6 a^{2} x^{4} b^{2}+4 a^{3} b \,x^{2}+a^{4}\right ) \sqrt {x \left (b \,x^{2}+a \right )}}\) | \(139\) |
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Time = 0.67 (sec) , antiderivative size = 121, normalized size of antiderivative = 0.80 \[ \int \frac {\sqrt {x}}{\left (a x+b x^3\right )^{9/2}} \, dx=\frac {{\left (256 \, b^{5} x^{10} + 896 \, a b^{4} x^{8} + 1120 \, a^{2} b^{3} x^{6} + 560 \, a^{3} b^{2} x^{4} + 70 \, a^{4} b x^{2} - 7 \, a^{5}\right )} \sqrt {b x^{3} + a x} \sqrt {x}}{21 \, {\left (a^{6} b^{4} x^{12} + 4 \, a^{7} b^{3} x^{10} + 6 \, a^{8} b^{2} x^{8} + 4 \, a^{9} b x^{6} + a^{10} x^{4}\right )}} \]
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\[ \int \frac {\sqrt {x}}{\left (a x+b x^3\right )^{9/2}} \, dx=\int \frac {\sqrt {x}}{\left (x \left (a + b x^{2}\right )\right )^{\frac {9}{2}}}\, dx \]
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\[ \int \frac {\sqrt {x}}{\left (a x+b x^3\right )^{9/2}} \, dx=\int { \frac {\sqrt {x}}{{\left (b x^{3} + a x\right )}^{\frac {9}{2}}} \,d x } \]
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Time = 0.31 (sec) , antiderivative size = 147, normalized size of antiderivative = 0.97 \[ \int \frac {\sqrt {x}}{\left (a x+b x^3\right )^{9/2}} \, dx=\frac {{\left ({\left (x^{2} {\left (\frac {158 \, b^{5} x^{2}}{a^{6}} + \frac {511 \, b^{4}}{a^{5}}\right )} + \frac {560 \, b^{3}}{a^{4}}\right )} x^{2} + \frac {210 \, b^{2}}{a^{3}}\right )} x}{21 \, {\left (b x^{2} + a\right )}^{\frac {7}{2}}} - \frac {4 \, {\left (6 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{4} b^{\frac {3}{2}} - 15 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} a b^{\frac {3}{2}} + 7 \, a^{2} b^{\frac {3}{2}}\right )}}{3 \, {\left ({\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} - a\right )}^{3} a^{5}} \]
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Timed out. \[ \int \frac {\sqrt {x}}{\left (a x+b x^3\right )^{9/2}} \, dx=\int \frac {\sqrt {x}}{{\left (b\,x^3+a\,x\right )}^{9/2}} \,d x \]
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